1-1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192,16384
2- 7F+1==80 hex or 128 dec ?
3- PI=3.141xx ( best I can do)
4- sq. root of 2 1.414
5- RMS of 100 VAC= 70.7
6- no
7- Jensen
8- BUD Lite
9- I don't like working on cars, I do chaner my own oil ( Ford)
10- (3.3 to 6.7), (1.5 to 7.5), ( ? )
11- CCW 12 RPM
12- 8 fingers two thumbs
13- 1 and Square Root of a Negative Number
Date: 01/25/97 at 19:04:00
From: Dustin Pedlar
Subject: Square root of negative numbers
Is it possible to find the square root of a negative number and if so,
to what number system do these square roots belong? Could you please
explain how this number system works?
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Date: 01/25/97 at 20:47:34
From: Doctor Wallace
Subject: Re: Square root of negative numbers
Hi Dustin!
As you no doubt know, a square root is a number that when multiplied
by itself is equal to a given number. For example, 4 is the square
root of 16, since 4 x 4 = 16. Note, however, that -4 x -4 = 16, too.
We call 4 the positive square root of 16, and -4 the negative square
root of 16.
Now, you want to know if we can find the square root of a negative
number. Let's take -16. We need to find a number, call it x, such
that:
x times x (x^2) = -16
Now, we know that any number times itself must be positive, not
negative. Therefore, there is no such number x in the set of real
numbers.
A number x is defined, however, in the set of complex numbers. The
complex numbers are a superset of the real numbers. That is, the
complex numbers form a bigger set. The reals are a subset of the
complex.
A complex number has the form a + bi, where a and b are real numbers
and the i is a special number. The "a" is called the real part; the
"bi" is called the imaginary part. If we let a equal 0, then we have
an imaginary number. The set of imaginary numbers is also a subset of
the complex numbers. If we let b equal 0, then we have a regular real
number. This is why the reals are a subset of the complex: the reals
are just complex numbers that all have b=0, that is, no imaginary
part.
Now, the number i is defined to be equal to the square root of -1.
This means that i^2 (i squared) is equal to -1. So now we can find
the square root of -16.
Since -16 = (-1) 16, we can write:
sqr(-16) = sqr(-1) times sqr(16) (property of square roots)
sqr(-16) = i times 4
This is usually written as 4i. We can check by squaring 4i. We get
4 x 4 = 16 times i x i = sqr(-1) times sqr(-1) = -1, giving 16 times
-1 or -16.
I looked this up give me credit
How did i do ?