backendcode
Member
Hello Everyone, I am very new to PLC programming and trying to learn PLC by myself. I found this awesome forum and would like to get some advice on my project at work.
Project. I have 4 conveyors with 4 proximity sensors, 1 proximity on each conveyor. Each conveyor is controlled by an individual motor.
1. The operator will put the part(company product) on the first conveyor and will make sure put on top of the proximity sensor.
2. Before the motor1 turns on and move the part, the proximity sensor 1 will check the condition on the 2nd conveyor and see the state of proximity sensor 2 of conveyor 2. If 2nd conveyor has already part on it, conveyor 1 won't On and will not move the part to the 2nd conveyor.
3. same logic will apply to conveyor 3 and 4.
I created a program. I don't have actual PLC processor right now to test it but can someone look into the program and tell me if I did right or no.
Pic attached
Note: I respect everyone's time and not looking for someone to do this project for me. I will try to finish my project and you can correct me and advise me to do better way. Thank you
Best,
Backendcode
Project. I have 4 conveyors with 4 proximity sensors, 1 proximity on each conveyor. Each conveyor is controlled by an individual motor.
1. The operator will put the part(company product) on the first conveyor and will make sure put on top of the proximity sensor.
2. Before the motor1 turns on and move the part, the proximity sensor 1 will check the condition on the 2nd conveyor and see the state of proximity sensor 2 of conveyor 2. If 2nd conveyor has already part on it, conveyor 1 won't On and will not move the part to the 2nd conveyor.
3. same logic will apply to conveyor 3 and 4.
I created a program. I don't have actual PLC processor right now to test it but can someone look into the program and tell me if I did right or no.
Pic attached
Note: I respect everyone's time and not looking for someone to do this project for me. I will try to finish my project and you can correct me and advise me to do better way. Thank you
Best,
Backendcode